Standards2030

A new vision for K-12 Science Standards
Home Knowledge Base Syllabus
Home
Working on:
K-12 Physics
Select Knowledge Base
Statements
Manage Statements Add/Edit Statement Prerequisite Graph View by Category
Actions
Manage Actions Add/Edit Action Prerequisite Graph View by Category
Learning Goals
Manage Learning Goals Add/Edit Learning Goal View by Category
Categories
Terms Pairs

Manage Statements

Filters & Search

Clear All
0 selected
Label Description LG Status Operations
ForceStrengthDirection A force is described by two characteristics: its strength and its direction. 0 Draft Edit
ForceStrengthDirection (Copy) A force is described by two characteristics: its strength and its direction. 0 Draft Edit
ForceStrengthDirection (Copy) A force is described by two characteristics: its strength and its direction. 0 Draft Edit
ForceStrengthDirection (Copy) (Copy) A force is described by two characteristics: its strength and its direction. 0 Draft Edit
ForcesVectors Forces are vectors. 0 Draft Edit
ForcesVectors (Copy) Forces are vectors. 0 Draft Edit
ForceUnit The SI unit for force is the newton, N. A force of magnitude 1 N imparts an acceleration of $1 \, \mathrm{m/s}^2$ to an object of mass 1 kg. $1 \, \mathrm{N} = 1 \, \mathrm{kg \cdot m/s}^2$. 0 Deprecated Edit
ForceUnit (Copy) The SI unit for force is the newton, N. A force of magnitude 1 N imparts an acceleration of $1 \, \mathrm{m/s}^2$ to an object of mass 1 kg. $1 \, \mathrm{N} = 1 \, \mathrm{kg \cdot m/s}^2$. 0 Draft Edit
ForceUnit (Copy) (Copy) The SI unit for force is the newton, N. A force of magnitude 1 N imparts an acceleration of $1 \, \mathrm{m/s}^2$ to an object of mass 1 kg. $1 \, \mathrm{N} = 1 \, \mathrm{kg \cdot m/s}^2$. 0 Draft Edit
GPEEqnUnits The equation for gravitational potential energy relative to a reference point is $\text{GPE}=m g h$, where $\text{GPE}$ is the object's gravitational potential energy, in joules, $m$ is the object's mass, in kilograms, $g$ is the acceleration due to gravity, in meters per second squared, and $h$ is the object's height above the reference point, in meters. 0 Ready Edit
GPEEqnUnits (Copy) The equation for gravitational potential energy relative to a reference point is $\text{GPE}=m g h$, where $\text{GPE}$ is the object's gravitational potential energy, in joules, $m$ is the object's mass, in kilograms, $g$ is the acceleration due to gravity, in meters per second squared, and $h$ is the object's height above the reference point, in meters. 0 Draft Edit
GravitationalPotentialEnergy Gravitational potential energy is the energy that an object has because of its position in a gravitational field. 0 Ready Edit
GravitationalPotentialEnergy (Copy) Gravitational potential energy is the energy that an object has because of its position in a gravitational field. 0 Draft Edit
GravityDirection The direction of the gravitational force exerted on object 1 by object 2 is towards object 2. 0 Ready Edit
GravityDirection (Copy) The direction of the gravitational force exerted on object 1 by object 2 is towards object 2. 0 Draft Edit
GravityDirection (Copy) (Copy) The direction of the gravitational force exerted on object 1 by object 2 is towards object 2. 0 Draft Edit
GravityEquation The magnitude of the gravitational force $F_\text{g}$ of object A on object B is $F_\text{g}=G \frac{m_\text{A} m_\text{B}}{d^2}$ where $G = 6.67 \times 10^{-11} \, \mathrm{N \cdot m}^2/\mathrm{kg}^2$ is the universal gravitational constant, $m_\text{A}$ and $m_\text{B}$ are the masses of the two objects, in kilograms and $d$ is the distance between them, in meters. 6 Ready Edit
GravityEquation (Copy) The magnitude of the gravitational force $F_\text{g}$ of object A on object B is $F_\text{g}=G \frac{m_\text{A} m_\text{B}}{d^2}$ where $G = 6.67 \times 10^{-11} \, \mathrm{N \cdot m}^2/\mathrm{kg}^2$ is the universal gravitational constant, $m_\text{A}$ and $m_\text{B}$ are the masses of the two objects, in kilograms and $d$ is the distance between them, in meters. 0 Draft Edit
GravityEquation (Copy) The magnitude of the gravitational force $F_\text{g}$ of object A on object B is $F_\text{g}=G \frac{m_\text{A} m_\text{B}}{d^2}$ where $G = 6.67 \times 10^{-11} \, \mathrm{N \cdot m}^2/\mathrm{kg}^2$ is the universal gravitational constant, $m_\text{A}$ and $m_\text{B}$ are the masses of the two objects, in kilograms and $d$ is the distance between them, in meters. 0 Draft Edit
GravityEquation (Copy) (Copy) The magnitude of the gravitational force $F_\text{g}$ of object A on object B is $F_\text{g}=G \frac{m_\text{A} m_\text{B}}{d^2}$ where $G = 6.67 \times 10^{-11} \, \mathrm{N \cdot m}^2/\mathrm{kg}^2$ is the universal gravitational constant, $m_\text{A}$ and $m_\text{B}$ are the masses of the two objects, in kilograms and $d$ is the distance between them, in meters. 0 Draft Edit
GravityExists A gravitational interaction exists between any two objects having mass. 0 Ready Edit
GravityExists (Copy) A gravitational interaction exists between any two objects having mass. 0 Draft Edit
GravitySpherePoint The gravitational force exerted by an extended, spherically-symmetric object is identical to the force exerted by a point particle, of the same mass, located at the center of the object. 0 Ready Edit
GravitySpherePoint (Copy) The gravitational force exerted by an extended, spherically-symmetric object is identical to the force exerted by a point particle, of the same mass, located at the center of the object. 0 Draft Edit
GravitySpherePoint (Copy) (Copy) The gravitational force exerted by an extended, spherically-symmetric object is identical to the force exerted by a point particle, of the same mass, located at the center of the object. 0 Draft Edit
GravityStrengthDistance The strength of the gravitational force of one object on another object is proportional to the inverse square of the distance between the objects. 0 Ready Edit
GravityStrengthDistance (Copy) The strength of the gravitational force of one object on another object is proportional to the inverse square of the distance between the objects. 0 Draft Edit
GravityStrengthMass The strength of the gravitational force of one object on another object is directly proportional to the mass of each of the objects. 0 Ready Edit
GravityStrengthMass (Copy) The strength of the gravitational force of one object on another object is directly proportional to the mass of each of the objects. 0 Draft Edit
GravityWeak The force of gravity is so weak that unless at least one of the objects is very large, it can be ignored. 0 Ready Edit
GravityWeak (Copy) The force of gravity is so weak that unless at least one of the objects is very large, it can be ignored. 0 Draft Edit
GravityWeak (Copy) (Copy) The force of gravity is so weak that unless at least one of the objects is very large, it can be ignored. 0 Draft Edit
GreaterAccelGreaterSpeedChange In equal time intervals, an object undergoing a greater acceleration will experience a greater change of speed than an object undergoing a lesser acceleration. 0 Deprecated Edit
GreaterAccelGreaterSpeedChange (Copy) In equal time intervals, an object undergoing a greater acceleration will experience a greater change of speed than an object undergoing a lesser acceleration. 0 Draft Edit
GreaterAccelGreaterSpeedChange (Copy) (Copy) In equal time intervals, an object undergoing a greater acceleration will experience a greater change of speed than an object undergoing a lesser acceleration. 0 Draft Edit
GreaterDurationGreaterVelChange Given equal net forces exerted on two objects having equal masses, the object experiencing the net force for the greater duration will have the greater change of velocity. 6 Ready Edit
GreaterDurationGreaterVelChange (Copy) Given equal net forces exerted on two objects having equal masses, the object experiencing the net force for the greater duration will have the greater change of velocity. 0 Draft Edit
GreaterDurationGreaterVelChange (Copy) (Copy) Given equal net forces exerted on two objects having equal masses, the object experiencing the net force for the greater duration will have the greater change of velocity. 0 Draft Edit
GreaterDurationGreaterVelChange (Copy) (Copy) Given equal net forces exerted on two objects having equal masses, the object experiencing the net force for the greater duration will have the greater change of velocity. 0 Draft Edit
GreaterForceGreaterVelChange Given net forces exerted for the same duration on two objects having equal masses, the object experiencing the greater net force will have a greater change in velocity. 0 Ready Edit
GreaterForceGreaterVelChange (Copy) Given net forces exerted for the same duration on two objects having equal masses, the object experiencing the greater net force will have a greater change in velocity. 0 Draft Edit
GreaterForceGreaterVelChange (Copy) Given net forces exerted for the same duration on two objects having equal masses, the object experiencing the greater net force will have a greater change in velocity. 0 Draft Edit
GreaterMassLesserVelChange Given equal net forces acting on two objects for the same duration, the less-massive object will experience the greater change of velocity. 0 Ready Edit
GreaterMassLesserVelChange (Copy) Given equal net forces acting on two objects for the same duration, the less-massive object will experience the greater change of velocity. 0 Draft Edit
GreaterSpeedGreaterDist In equal time intervals, an object with a greater speed will travel a greater distance than an object with a lesser speed. 4 Ready Edit
GreaterSpeedGreaterDist (Copy) In equal time intervals, an object with a greater speed will travel a greater distance than an object with a lesser speed. 0 Draft Edit
HookesLawSpring A Hooke's Law spring is a spring for which the restoring force is linearly proportional to, and in the opposite direction from, the displacement from its equilibrium position, i.e. $F =-k \Delta x$, where $F$ is the restoring force, in newtons, $k$ is the spring constant, in newtons per meter, and $\Delta x=\left(x-x_0\right)$ is the displacement, in meters, from the spring's current extension, $x$, to its equilibrium extension, $x_0$. 0 Ready Edit
HookesLawSpring (Copy) A Hooke's Law spring is a spring for which the restoring force is linearly proportional to, and in the opposite direction from, the displacement from its equilibrium position, i.e. $F =-k \Delta x$, where $F$ is the restoring force, in newtons, $k$ is the spring constant, in newtons per meter, and $\Delta x=\left(x-x_0\right)$ is the displacement, in meters, from the spring's current extension, $x$, to its equilibrium extension, $x_0$. 0 Draft Edit
Hypothesis A hypothesis is a type of testable explanation (model) of natural systems or phenomena, or of evidence from an investigation. 0 Ready Edit
Hypothesis (Copy) A hypothesis is a type of testable explanation (model) of natural systems or phenomena, or of evidence from an investigation. 0 Draft Edit

Page 10 of 18 (899 total statements, showing 50 on this page)